Answer:
The likelihood that he or she has a pet given that a student does not have a sibling is:
Option: D ( 60%)
Step-by-step explanation:
Let A denote the event that a student does not have a sibling.
Let B denote the event that a students has a pet.
Then A∩B denotes the event that the student does not have a sibling but has a pet.
Let P denote the probability of an event.
Then, we are asked to find:
P(B|A)
We know that:
[tex]P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}[/tex]
Also from the table we have:
P(A)=0.25
and P(A∩B)=0.15
Hence,
[tex]P(B|A)=\dfrac{0.15}{0.25}\\\\P(B|A)=\dfrac{3}{5}\\\\P(B|A)=0.6[/tex]
which in percentage is:
[tex]0.6\times 100=60\%[/tex]
Hence, the likelihood is:
60%
