Answer: Tt is unlikely to have change in the sample mean score is less than 10​ points .
Step-by-step explanation:
Given : Mean : [tex]\mu=17\text{ points}[/tex]
Standard deviation : [tex]\sigma= 67\text{ points}[/tex]
Sample size : n= 100
We assume that the change in students scores are normally distributed.
Let X be the random variable that represents the change in students scores .
Z score : [tex]z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]
For x = 10
[tex]z=\dfrac{10-17}{\dfrac{67}{\sqrt{100}}}\approx-1.045[/tex]
By using the standard normal distribution table , the probability  that the change in the sample mean score is less than 10​ points :-
[tex]P(X<10)=P(z<-1.045)=0.1480115[/tex]
Since the calculated probability is less than 0.5.
So , we say that it is unlikely to have change in the sample mean score is less than 10​ points .