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The period T in seconds of a simple pendulum of length L in feet is given by T=2π√L/32. Determine the length in feet of a simple pendulum whose period is 8.72 seconds. Round your answer to the nearest foot.

1972 feet.
387 feet.
62 feet.
256 feet.

Respuesta :

carlosego
For this case we have the following equation:
 T = 2π√L / 32
 Clearing L we have:
 T / 2π = √L / 32
 (T / 2π) ^ 2 = L / 32
 L = 32 * (T / 2π) ^ 2
 Substituting values:
 L = 32 * (8.72 / (2 * (3.14))) ^ 2
 L = 61.69694511 feet
 Round to the nearest foot:
 L = 62 feet
 Answer:
 L = 62 feet
aencabo
 In this situation, you have to use the equation
T = 2π√L / 32
 We need to find L so we have:
 T / 2π = √L / 32
 (T / 2π) ^ 2 = L / 32
 L = 32 * (T / 2π) ^ 2

 Substitute the values:
 L = 32 * (8.72 / (2 * (3.14))) ^ 2
 L = 61.69694511 feet
 L = 62 feet
 So the Answer is
 L = 62 feet

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