Respuesta :
 Solution.
Initial angular velocity ωi = 0.330 × 2π rad/sec
                     = 2.0737 rad/sec
The initial moment of inertia li = 0.5×M×r²
                        = 0.5 × 120 × 1.8²
                        = 194.4 kgm²
But the angular momentum is given by the product of moment of inertia and the angular velocity.
 = li × ωi
 = 2.0737 × 194.4
 = 403.13 kg.m²/s which is constantÂ
Child moment of inertia (point mass) = m × r²Â
                             = 27.5 × 1.8²
                             = 27.5 × 3.24
                             = 89.1 kgm²
Thus, the final moment of inertia if = 194.4 + 89.1 = 283.5 kgm²
Therefore; the final speed: =403.13/ 283.5Â
                      = 1.422 rad/sec
This is equivalent to;
 1.422/2π = 0.2263 rev/s
                   Â
Initial angular velocity ωi = 0.330 × 2π rad/sec
                     = 2.0737 rad/sec
The initial moment of inertia li = 0.5×M×r²
                        = 0.5 × 120 × 1.8²
                        = 194.4 kgm²
But the angular momentum is given by the product of moment of inertia and the angular velocity.
 = li × ωi
 = 2.0737 × 194.4
 = 403.13 kg.m²/s which is constantÂ
Child moment of inertia (point mass) = m × r²Â
                             = 27.5 × 1.8²
                             = 27.5 × 3.24
                             = 89.1 kgm²
Thus, the final moment of inertia if = 194.4 + 89.1 = 283.5 kgm²
Therefore; the final speed: =403.13/ 283.5Â
                      = 1.422 rad/sec
This is equivalent to;
 1.422/2π = 0.2263 rev/s
                   Â
