contestada

supposed to vacuum cleaner uses 120 J of electrical energy. If 45 J used to pull air into a vacuum cleaner, how efficient is the vacuum cleaner?

Respuesta :

calculista

we know that

Power efficiency is defined as the ratio of the output power divided by the input power:

so

[tex] efficiency =\frac{ Power\ out}{Power\ in} *100 [/tex]

in this problem

[tex] Power\ out=45J\\ Power\ in=120J [/tex]

Substitute in the formula above

[tex] efficiency =\frac{ 45}{120} *100 [/tex]

[tex] efficiency =37.5 [/tex]%

therefore

the answer is

the efficient is [tex] 37.5 [/tex]%

ysabayomi

Answer:

The efficiency of the vacuum cleaner is 37.5%

Explanation:

The efficiency of a machine can be calculated as

Efficiency = (work output ÷ work input) × 100%

Work output (according to the question) is 45J of electrical energy

work input (according to the question) is 120J of electrical energy

Efficiency = (45 ÷ 120) × 100

Efficency = 37.5 %

The efficiency of the vacuum cleaner is 37.5%

NOTE: Vacuum cleaner is a machine and a machine can not be 100% efficient

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