Answer: 562.5 m
[tex]Displacement = velocity \times time[/tex]= area under the curve in velocity-time graph
The area of the quadrilateral formed by the graph is given by:
[tex]A=\frac{(a+b)}{2} h[/tex]
where, a and b are two parallel sides of the quadrilateral, h is the perpendicular distance between the two parallel sides.
from the given graph,
[tex]a=10 m/s[/tex]
[tex]b=35 m/s[/tex]
[tex]h=25 s[/tex]
Hence, [tex]A= \frac{(10+35) m/s}{2}\times 25 s=562.5 m[/tex]
The area under graph = 562.5 m. Hence, the total displacement is 562.5 m.
