Answer:
Electrical Force by a factor of [tex]2.23 \times 10^{39}[/tex]
Explanation:
Known values
magnitude of the charge of an electron |e| = [tex]1.6 \times 10^{-19}[/tex]
magnitude of the charge of a proton |e| = [tex]1.6 \times 10^{-19}[/tex]
Note: magnitude means we only consider positive numerical value
mass of an electron m = [tex]9.1 \times 10^{-31}[/tex] kg
mass of an electron M = [tex]1.7 \times 10^{-27}[/tex] kg
[tex]Electric force,F_e = \frac{ke^{2}}{r^{2}}[/tex]
[tex]Gravitational force,F_g = \frac{GMm}{r^{2} }[/tex]
[tex]\frac{Electric force }{Gravitational force} = \frac{\frac{ke^{2}}{r^{2}}}{ \frac{GMm}{r^{2} }} \\\\\frac{Electric force }{Gravitational force} = \frac{ke^2}{GMm} \\\\\frac{Electric force }{Gravitational force} = \frac{9 \times 10^9 \times (1.6 \times 10^{-19})^2}{6.67 \times 10^{-11} \times 1.7 \times 10^{-27} \times 9.1 \times 10^{-31}} \\\\\frac{Electric force }{Gravitational force} = 2.23 \times 10^{39}[/tex]
