Respuesta :
(v^2)=(u^2)+(2*a*s) where v is final speed
u is initial speed
a is acceleration
s is displacement
U=sin30 * 29.4
v=0
a=9.81
u is initial speed
a is acceleration
s is displacement
U=sin30 * 29.4
v=0
a=9.81
Answer:
22.05 meters
Explanation:
In order to get the answer, basically it is a distance we are looking for.
We are going to get familiar with the formula of displacement:
Δx[tex]=vt[/tex]
[tex]v[/text]= average velocity
[tex]t[/text]= time in motion
Because it is a projectile in motion thrown at a 29.4 m/s with an angle of 30°, we need to find the vertical part of that velocity.
The vertical part is given by the [tex]sin[/tex] of the angle of 30°
that is
[tex]29.4\frac{m}{s^{2}} sin(30)=v_{y} \\ \\29.4\frac{m}{s^{2}}(0.5)=v_{y}\\14.7\frac{m}{s}=v_{y}[/tex]average velocity
Now
Δ[tex]v_{y} =v_{f}-v_{i} \\v_{f}=-14.7 m/s[/tex]\\ because the baseball goes the opposite direction when is going down until it gets to the grown. Then [tex]v_{i}=14.7m/s[/tex]
[tex]v_{y} =v_{f}-v_{i}\\v_{y} =-14.7m/s-14.7m/s=-29.4m/s[/tex]
and using this formula
[tex]v_{y}=-gt[/tex]
we divide both sides by [tex]-g[/tex] and we get [tex]t[/tex]
[tex]-29.4m/s=-9.8m/s^{2}*t \\t=\frac{-29.4m/s}{-9.8m/s^{2}}=3s[/tex]
Finally 3 seconds is the time in motion, so we divide by two because we just need the time going up, that happens to be the same time going down.
[tex]\frac{t}{2}=\frac{3}{2}=1.5s[/tex] time in motion
Δx[tex]=vt[/tex]
[tex]v[/text]= average velocity=[tex]14.7\frac{m}{s}[/tex]
[tex]t[/text]= time in motion=[tex]1.5s[/tex]
[tex]14.7\frac{m}{s}*1.5s=22.05m[/tex]
