A juggler is performing her act using several balls. She throws the balls up at an initial height of 4 feet, with a speed of 15 feet per second. If the juggler doesn't catch one of the balls, about how long does it take the ball to hit the floor?

Hint: Use H(t) = _16t2 + vt + s.

7.52 seconds
1.15 seconds
0.47 second
0.22 second

Respuesta :

The correct answer between all the choices given is the second choice, which is 1.15 seconds. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

Answer:

The ball will take 1.15 seconds to hit the floor.

Explanation:

It is given that,

A juggler is performing her act using several balls. The height as a function of time is given by :

[tex]h(t)=-16t^2+vt+s[/tex].............(1)

where

v is the speed of the ball

s is initial height

t is time taken

Putting h(t) = 0 and solving equation (1)

[tex]-16t^2+vt+s=0[/tex]

[tex]-16t^2+15t+4=0[/tex]

On solving above equation using graphing calculator and solving for t we get, t = 1.154 seconds

Hence, the correct option is (b) " 1.15 seconds ".

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Q&A Education