contestada

the length of a rectangular sign is 4 times it's width. if the sign's perimeter is 30 inches, what is the area?

Respuesta :

Answer:

36

Step-by-step explanation:

Width = x

Length = 4x

Perimeter = Width + Width + Length + Length (Because there are four sides; two sides are the widgth and two sides are the length)

30 (because 30 is given as the perimeter) = x + x + 4x + 4x

30 = 10x

x = 3

Width = 3

Length = 4(3) = 12

Area = Width * Length

Area = 3 * 12 = 36

Lanuel

The area of the rectangular sign is equal to 36 square inches, if its perimeter is 30 inches.

  • Let the length of the rectangular sign be L.
  • Let the width of the rectangular sign be W.

Given the following data:

  • Perimeter of rectangular sign = 30 inches.

Translating the word problem into an algebraic equation, we have;

[tex]L = 4W[/tex]

Mathematically, the perimeter of a rectangle is given by the formula;

[tex]P = 2(L+W)\\\\30 = 2(4W + W)\\\\30 = 2(5W)\\\\30 = 10W\\\\W = \frac{30}{10}[/tex]

Width, W = 3 inches

For its length:

[tex]L = 4W\\\\L = 4(3)[/tex]

Length, L = 12 inches.

Now, we can determine the area of the rectangular sign by using the formula:

[tex]Area = LW\\\\Area = 12(3)[/tex]

Area = 36 square inches.

Therefore, the area of the rectangular sign is equal to 36 square inches.

Find more information: brainly.com/question/897975

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