Only two stable isotopes of chlorine exist. 35Cl has a mass of 34.96885 amu and 37Cl has a mass of 36.9659 amu. Given that the atomic mass of chlorine is 35.453, calculate the isotopic abundance of 37Cl. (Enter your answer as a decimal number between zero and one.)

Respuesta :

Answer: The isotopic abundance of Cl- 37 is 0.2424.

Explanation:

Mass of isotope - 35 = 34.96885 amu

% abundance of isotope -35= x% = [tex]\frac{x}{100}[/tex]

Mass of isotope - 37 = 36.9659 amu.

% abundance of isotope-37 = (100-x)% = [tex]\frac{100-x}{100}[/tex]

Formula used for average atomic mass of an element :

[tex]\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})[/tex]

[tex]35.453=\sum[(34.96885 \times \frac{x}{100})+(36.9659 \times \frac{100-x}{100}]][/tex]

[tex]x=75.76\%[/tex]

[tex](100-75.76)=24.24\%=0.2424[/tex]

Therefore,  the isotopic abundance of Cl- 37 is 0.2424.

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