Respuesta :
1 + cos t = ( √3 + 2 ) /2
cos t = ( √3 + 2 ) / 2 - 1
cos t = ( √3 + 2 - 2 ) / 2
cos t = √3/2
t 1 = π/6, t 2 = 11π/6
Answer: C ) π/6, 11π/6.
cos t = ( √3 + 2 ) / 2 - 1
cos t = ( √3 + 2 - 2 ) / 2
cos t = √3/2
t 1 = π/6, t 2 = 11π/6
Answer: C ) π/6, 11π/6.
Answer:
Option C is right
Step-by-step explanation:
[tex]1+cos\theta =\frac{\sqrt{3}+2 }{2} =\frac{\sqrt{3} }{2} +1[/tex]
Now we cancel 1 and get
[tex]cos\theta =\frac{\sqrt{3} }{2}[/tex]
The solutions would be positive for cos hence the angle lies in I quadrant, IV quadrant.
In I quadrant angle satisfying in the I quadrant, is 30 degrees, pi/6
In IV quadrant this would be 2pi-pi/6 = 11pi/6
Hence solution is
pi/6, 11 pi/6
OPtionC