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An envelope measures 8 inches by 15 inches. A pencil is placed in
the envelope at a diagonal forming a right triangle. What is the
length of the pencil?

Respuesta :

ricardoreyver
The length of the pencil would be 17. This could be easily found by using a^2 + b^2 = c^2. Please mark me brainliest it would be pretty cash money of you

Answer:

The length of the pencil is 17 inches.

Step-by-step explanation:

You need to do the Pythagorean theorem. For example, this is what I did, 8^2+15^2=x^2

64+225=x^2

289=x^2

the square root of 289 is 17.

hope this helps :)

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