First, solve for the volume of the ball bearings by the equation,
V = πd³ / 6
Substituting the value of diameter given,
V = π(1 cm)³ / 6 = π/6 cm³ = 0.5236 cm³
Divide the amount of material given by this volume,
n = 5.24 cm³ / 0.5236 cm³ = 10
Therefore, there are 10 ball bearings that may be formed.
