Respuesta :
Explanation:
Relation between work and change in kinetic energy is as follows.
[tex]W_{net} = \Delta K[/tex]
Also, [tex]\Delta K = K_{initial} - K_{final}[/tex]
= [tex](0 - 4.0 \times 10^{-17})[/tex] J
= [tex]-4.0 \times 10^{-17}[/tex] J
Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.
w = -Fd
[tex]-4.0 \times 10^{-17} J = -F \times 0.3 m[/tex]
F = [tex]1.33 \times 10^{-16}[/tex]
Therefore, relation between electric field and force is as follows.
E = [tex]\frac{F}{q}[/tex]
= [tex]\frac{1.33 \times 10^{-16}}{1.60 \times 10^{-19} C}[/tex]
= [tex]0.831 \times 10^{3}[/tex] C
Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is [tex]0.831 \times 10^{3}[/tex] C.
