Answer:
12.973 liters of H2S is required at STP.
Explanation:
The given equation is ,
2H2S + 3O2 --> 2SO2 + 2H2O , mass of reacting O2 is 27.8 g
The mole ratio is,
[tex]\frac{H2S}{O2} = \frac{2}{3}[/tex]
number of moles = m = [tex]\frac{mass of substance}{molecular weight of compound}[/tex]
for O2, m = [tex]\frac{27.8}{32}[/tex] (molecular weight of O2 is 32)
number of moles of H2S is
[tex](\frac{2}{3})(\frac{27.8}{32})[/tex]
now at STP, 1 mole of gas occupies 22.4 liters.
thus liters of H2S required are,
[tex](\frac{2}{3})(\frac{27.8}{32})(22.4)[/tex] = 12.973 liters
