alexia200228 alexia200228

04-12-2019
Mathematics

contestada

find the real zeros 4x²-16x + 2.5x

Respuesta :

04-12-2019

I am going to assume 2.5x is really 25x (typo).

First formulate the equality

[tex]

4x^2-16x+25x=0 \\

4x^2+9x=0 \\

x(4x+9)=0 \\

[/tex]

Now two results emerge.

[tex]x_1=0, x_2=-\dfrac{9}{4}[/tex].

Hope this helps.

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