Answer:
h = 0.255 meters
Explanation:
It is given that,
Mass of the block, m = 0.2 kg
Compression in the spring, x = 0.1 m
Spring constant of the spring, [tex]k=10^2\ N/m[/tex]
Let h is the maximum height reached by the block if the force were removed. Using the conservation of energy of the spring mass system as :
[tex]mgh=\dfrac{1}{2}kx^2[/tex]
[tex]h=\dfrac{1}{2mg}kx^2[/tex]
[tex]h=\dfrac{1}{2\times 0.2\times 9.8}\times 100\times (0.1)^2[/tex]
h = 0.255 meters
So, the maximum height reached by the block is 0.255 meters. Hence, this is the required solution.
