Respuesta :
Answer: 0.2420
Step-by-step explanation:
Let x be a random variable that represents the number of cars passed through the intersection per day .
As per given , we have
[tex]\mu=550000[/tex]
[tex]\sigma=100,000[/tex]
We assume that the number of cars on the interchange is approximately normally distributed.
∵ [tex]z=\dfrac{x-\mu}{\sigma}[/tex]
Then for x= Â 620,000, [tex]z=\dfrac{620000-550000}{100000}=0.7[/tex] Â
The probability more than 620,000 use the interchange on a random day :-
[tex]P(x>620000)=P(z>0.7)=1-P(z\leq0.7)\\\\=1-0.7580363=0.2419637\approx0.2420[/tex]
Hence, the probability more than 620,000 use the interchange on a random day= 0.2420