Answer:
total heat needed 6.173*10^5 j
Explanation:
Heat needed to convert 50° to boiling point
[tex]Q = m*c* dT[/tex]
where c is specific heat of water = 4190 j /kg K
= 0.250*4190*(100-50)
= 5237.5 j
Now heat required to convert water at 100 degree to vapour
=[tex]mL_f[/tex]
= 0.250*22.6x10^5
= 5.65*10^5
total heat needed = 5237.5 +5.65*10^5 = 6.173*10^5 j
