Answer:
[tex]\large \boxed{9.575 \times 10^{23}\text{ molecules}}[/tex]
Explanation:
1. Moles of oxygen
[tex]\text{Moles of O}_{2} = \text{50.88 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{1.590 mol O}_{2}[/tex]
2. Molecules of oxygen
[tex]\text{Molecules of O}_{2} = \text{1.590 mol O}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules O}_{2}}{\text{1 mol O}_{2}} = \mathbf{9.575 \times 10^{23}}\textbf{ molecules O}_{2}\\\\\text{There are $\large \boxed{\mathbf{9.575 \times 10^{23}}\textbf{ molecules of O}_{2}}$ in 50.88 g of oxygen.}[/tex]
