Answer: [tex]-\sqrt{3},\ +\sqrt{3}[/tex]
Step-by-step explanation:
The given quadratic equation :_ [tex]5x^2-15=0[/tex]
To solve this , we first add 15 on the both the sides of the above equation, we get
[tex]5x^2-15+15=0+15\\\\\Rightarrow\ 5x^2=15[/tex]
Now, we divide both sides by 5, we get
[tex]x^2=3[/tex]
Taking square roots on both the sides , we get
[tex]x=\pm\sqrt{3}[/tex]
Hence, the two possible solutions = [tex]-\sqrt{3},\ +\sqrt{3}[/tex]
