The standard deviation of the weights of elephants is known to be approximately 15 pounds. We wish to construct a 95% confidence interval for the mean weight of newborn elephant calves. Fifty newborn elephants are weighed. The sample mean is 244 pounds. The sample standard deviation is 11 pounds. Construct a 95% confidence interval for the population mean weight of newborn elephants. State the confidence interval. (Round your answers to two decimal places.) ,

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Answer:

The confidence interval is [240.87 , 247.13].

Step-by-step explanation:

Given : The standard deviation of the weights of elephants is known to be approximately 15 pounds. We wish to construct a 95% confidence interval for the mean weight of newborn elephant calves. Fifty newborn elephants are weighed. The sample mean is 244 pounds. The sample standard deviation is 11 pounds.

To find : Construct a 95% confidence interval for the population mean weight of newborn elephants. State the confidence interval?

Solution :

We have given that,

Sample mean, x =244

Standard deviation, s =11

Sample size, n =50

First we find the standard error,

[tex]\text{Standard error}=\frac{s}{\sqrt n}[/tex]

[tex]\text{Standard error}=\frac{11}{\sqrt{50}}[/tex]

[tex]\text{Standard error}=1.56[/tex]

Then we find the margin of error,

[tex]\text{Margin of error}=t_{\frac{\alpha}{2}}\times\text{Standard error} [/tex]

Applying t-table values,

[tex]t_{\frac{\alpha}{2}}[/tex] is the t-table value

Level of significance, [tex]\alpha = 0.05[/tex]

From standard normal table, two tailed value of with n-1 = 49 d.f is [tex]t_{\frac{\alpha}{2}}=2.01[/tex]

Substitute in the formula,

[tex]\text{Margin of error}=2.01\times1.56[/tex]

[tex]\text{Margin of error}=3.1356[/tex]

Now, The confidence of the interval is given by,

[tex]CI = x\pm \text{Margin of error}[/tex]

[tex]CI = 244\pm3.1356[/tex]

[tex]CI = 244-3.1356,244+3.1356[/tex]

[tex]CI = 240.8644,247.1356[/tex]

Therefore, The confidence interval is[ 240.87 , 247.13 ].

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