Respuesta :
Answer:
Work done, [tex]W=1.96\times 10^{-20}\ J[/tex]
Explanation:
It is given that,
Potential difference between the inner and outer surfaces of a cell membrane, [tex]\Delta V=123\ mV=123\times 10^{-3}\ V[/tex]
The inner surface is negative relative to the outer surface. Let W is the work required to eject a positive sodium ion (Na+) from the interior of the cell. Work done is given by :
[tex]W=q\Delta V[/tex]
q is the charge on electron
[tex]W=1.6\times 10^{-19}\ C\times 123\times 10^{-3}\ V[/tex]
[tex]W=1.96\times 10^{-20}\ J[/tex]
So, the work required to eject a positive sodium ion (Na+) from the interior of the cell is [tex]1.96\times 10^{-20}\ J[/tex]. Hence, this is the required solution.
