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What is the rate of change for the interval between 0 and 2 for the quadratic equation as f(x) = 2x2 + x – 3 represented in the table? (The table has this: Left side X and the options going down are -2, -1, 0, 1, 2. Right Side f(x) and the options going down are 3, -2, -3, 0, 7) THE ANSWER OPTIONS ARE: 1/5, 4, 5, 10

Respuesta :

carlosego
By definition the rate of change of a function is given by:
 [tex]AVR = \frac{f(x2) - f(x1)}{x2 - x1} [/tex]
 For the interval [0, 2] We have to make use of the table:
 [tex]f(0)=-3 f(2)=7[/tex]
 Therefore, substituting values in the given expression we have that the average change of rate is given by:
 [tex]AVR = \frac{7-(-3)}{2-0} [/tex]
 Rewriting we have:
 [tex]AVR = \frac{7+3}{2-0} [/tex]
 [tex]AVR = \frac{10}{2} [/tex]
 [tex]AVR = 5[/tex]
 Answer:
 the rate of change for the interval between 0 and 2 is:
 [tex]AVR = 5[/tex]
dewy32

Answer:

(C) 5

Step-by-step explanation:

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