Solve by elimination
-3x+y = -28
-x-6y = -3
~~~~~~~~~~~~~
Eliminate x:
-3x+y=-28
-x-6y=-3
~~~~~~~~~~~~~
-3x+y=-28
-3(-1)x-3(-6)y=(-3)(-3)
~~~~~~~~~~~~~
3x-1y=28
3x+18y=9
19y=-19
Therefore:
19y=-19
÷19 ÷19
y=[tex]\frac{-19}{19}[/tex]
y=1
~~~~~~~~~~~~~
3x-1y=28
y=-1
~~~~~~~~~~~~~
3x-1(-1)=28
3x+1=28
-1 -1
3x=28-1
3x=27
÷3 ÷3
x=[tex]\frac{27}{3}[/tex]
↑ They cancel each other out
x=9
~~~~~~~~~~~~~
x=9
y=-1
Answer is: (9,-1)
Answer:
X=9, y=-1
Explanation:
Multiply 2nd equation by -3 so you can eliminate x
-3(-x-6y)=-3(-3)
3x+18y=9
add first equation to modified second equation:
-3x+y=-28
3x+18y=9
Solve. 19y=-19
Y=-1
Find x by substituting y value into either equation:
-3x+y=-28
-3x+-1=-28
-3x=-27
x-9
check answer by substituting x and y values into either equation.
-3x+y=-28
-3(9)+-1=-28
-27-1=-28
-28=-28