In the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many liters of hydrogen gas will be produced from 75.0 milliliters of a 3.0 M HCl in an excess of Mg at STP? 1.1 liters 34 liters 2.52 liters 0.11 liters 0.23 liters NextReset © 2017 Edmentum. All rights reserved.

Respuesta :

Definition of molarity said is the number of moles per liter of solution

M= n/V(L) => n = M V (L)

n= 3.0 x 0.075 L = 0.225 Moles of HCl

According to the stoichiometry of the reaction 2 Mol. of HCl will produce 1 Mol. of H2. Then

0.225 mol HCl x 1 mol H2 /2 mol HCl = 0.1125 mol H2

1 mol of any ideal gas at STP condition occupy a molar volume equal to 22.4L. Then

0.1125 mol H2 x 22.4L/ 1mol = 2.52 L

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