Answer:
The equation of function A is [tex]x=-5[/tex] and the equation of function B is [tex]y=-5[/tex].
Step-by-step explanation:
The point slope form of a linear function is
[tex]y-y_1=m(x-x_1)[/tex]
Where m is slope.
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
It is given that the function A passing through the points (–5, –2) and (–5, 7).
The equation of function A is
[tex]y-(-2)=\frac{7-(-2)}{-5-(-5)}(x-(-5))[/tex]
[tex]y+2=\frac{7+2}{-5+5}(x+5)[/tex]
[tex]y+2=\frac{9}{0}(x+5)[/tex]
[tex](y+2)0=9(x+5)[/tex]
[tex]0=9(x+5)[/tex]
[tex]0=x+5[/tex]
[tex]x=-5[/tex]
It is given that the function B passing through the points (7, –5) and (–2, –5).
The equation of function B is
[tex]y-(-5)=\frac{-5-(-5)}{-2-7}(x-7)[/tex]
[tex]y+5=\frac{0}{-9}(x-7)[/tex]
[tex]y+5=0[/tex]
[tex]y=-5[/tex]
Therefore equation of function A is [tex]x=-5[/tex] and the equation of function B is [tex]y=-5[/tex].
