the equations are already in slope-intercept form, therefore
[tex] \bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\stackrel{\stackrel{slope}{\downarrow }}{m}x+\stackrel{\stackrel{y-intercept}{\downarrow }}{b}\\\\ y=mx+b \\\\ \cline{1-1} \end{array}~\hspace{8em}y=\stackrel{slope}{2}x\qquad y=\stackrel{slope}{4}x+1 [/tex]
so their slopes are 2 and 4.
parallel lines have exactly the same slope, these ones do not, so they're not parallel.
perpendicular lines, have negative reciprocal slopes, in short, their product gives -1, 2*4 ≠ -1, so they're not perpendicular either.
Answer: nethier perpendicular or parallel
Step-by-step explanation:
