In the circle, mBC=76degrees. The diagram is not drawn to scale. What is m angle BCP?
For a better understanding of the solution/explanation provided here, please go through the diagram in the file that has been attached.
To solve this question we will use the following theorem: "An Angle formed by a chord and a tangent that intersect on a circle is half the measure of the intercepted arc ".
As can be seen from the diagram, the intercepted arc is BC and it's angle is [tex] \angle BOC=76^{\circ} [/tex].
Therefore, as per the theorem, [tex] m\angle BCP=\frac{1}{2}\times m\angle BOC [/tex]
[tex] \therefore m\angle BCP=\frac{1}{2}\times 76^{\circ}=38^{\circ} [/tex]
Thus the third option is the correct option.
The measured ∠BCP is 104°.
A cyclic quadrilateral is a quadrilateral that is inscribed in a circle in which all its vertices touch the circle.
Analysis:
∠ABC + ∠BAD = 180 ( opposite angles of a cyclic quadrilateral sum up to 180)
∠BAD + 76 = 180
∠BAD = 180 - 76 = 104°
∠BCP = ∠BAD ( angles in alternate segments of a circle are equal)
Therefore, ∠BCP = 104°
In conclusion, ∠BCP = 104°
Learn more about cyclic quadrilateral: brainly.com/question/24142962
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