Respuesta :

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[tex]f(x)=x-6;\ g(x)=x^\frac{1}{2}(x+3)\\\\f(x)\cdot g(x)=(x-6)\cdot x^\frac{1}{2}(x+3)=x^\frac{1}{2}(x-6)(x+3)=x^\frac{1}{2}(x^2+3x-6x-18)\\\\=x^\frac{1}{2}(x^2-3x-18)=(x^2-3x-18)\sqrt{x}[/tex]

Answer:

(x²-3x-18)√x, or (x-6)(x+3)√x

Step-by-step explanation:

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