angeliqu185986
angeliqu185986
05-05-2018
Mathematics
contestada
the arc lenght of pi over 3 and 10m
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jdoe0001
jdoe0001
05-05-2018
[tex]\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ ------\\ r=10\\ \theta =\frac{\pi }{3} \end{cases}\implies s=10\cdot \cfrac{\pi }{3}\implies s=\cfrac{10\pi }{3}[/tex]
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