A set of weights includes a 4 lb barbell and 6 pairs of weight plates. Each pair of plates weighs
20 lb. If x pairs of plates are added to the barbell, the total weight of the barbell and plates in
pounds can be represented by f x( ) = 20x + 4.

What is the range of the function for this situation?

Please explain.

Respuesta :

The range of the function is the distance from the maximum of the function to the minimum of the function. The minimum amount of pairs of plates that you can add to the bar (x) is 0, meaning you add no plates. The maximum amount of plates that you can add to the bar is 6, because this is how many plates come in one weight set. The range of the function is y values, and 0 and 6 are x values, so we must plug these values into the function to find the range values.

f(x) = 20x + 4 = 20(0) + 4 = 0 + 4 = 4

f(x) = 20x + 4 = 20(6) + 4 = 120 + 4 = 124

Therefore, the range of the function is 120 pounds, or from [4, 124].

Hope this helps!

The range of a function is the possible output values of the function. The range of [tex]f(x) =20x + 4[/tex] is [4,124]

Given that:

[tex]f(x) =20x + 4[/tex]

To determine the range of the function, we simply determine the value of f(x) using the input values

When no pair is added (this means x = 0).

So, we have:

[tex]f(0) =20 \times 0 + 4[/tex]

[tex]f(0) = 0 + 4[/tex]

[tex]f(0) = 4[/tex]

When 4 pairs are added (this means x = 4).

So, we have:

[tex]f(4) = 20 \times 4 + 4[/tex]

[tex]f(4) = 84[/tex]

When 6 pairs are added (this means x = 6).

So, we have:

[tex]f(6) = 20 \times 6 + 4[/tex]

[tex]f(6) = 124[/tex]

f(6) is greater than f(4).

i.e. [tex]124 > 84[/tex]

So, the range of the function is: [0,124] or [tex]4 \le x \le 124[/tex]

Read more about range at:

https://brainly.com/question/1632425

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