When flying at an altitude of 5 miles, the lines of sight to the horizon looking north and south make about a 173.7 degree angle. how much of the longitude line directly under the plane is visible from 5 miles high?
5 miles high is one of the sides of a triangle depending on accuracy level h^2=x^2+y^2 we don't have 2 distances Tan A=O/a O=a tan A We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground O=5×tan(173.7/2)=90.854033512 The distance he can see is: 90.85*2~181.7 miles
Now we need to find the distance between lines: The north south distance between each line is 69 miles thus the number of degrees he will see will be: 181.7/69 =2 19/30
