Molten calcium bromide is separeted: :
CaBr₂(l) →
Ca(l) + Br₂(l),
but first ionic bonds in this salt are separeted
because of the heat:
CaBr₂(l) →
Ca²⁺(l) + 2Br⁻(l).
Reaction of reduction at cathode(-): Ca²⁺(l) + 2e⁻ → Ca(l).
Reaction of oxidation at anode(+): 2Br⁻(l) → Br₂(l) + 2e⁻.
The anode is positive and the cathode is negative.
Answer: Bromine is produced at anode.
Explanation:
On electrolysis of molten calcium bromide, the following reaction occurs:
[tex]CaBr_2(l))\rightarrow Ca^{2+}(l)+2Br^-(l)[/tex]
In molten [tex]CaBr_2[/tex] there are [tex]Ca^{2+}[/tex] and [tex]Br^-[/tex] ions.
At cathode which is a negative terminal , cations will be reduced.At anode which is a positive terminal , anions will be oxidized.
At cathode: [tex]Ca^{2+}+2e^- \rightarrow Ca(s)[/tex]
So, calcium is deposited at cathode.
At anode: [tex]2Br^-\rightarrow Br_2+2e^-[/tex]
At anode [tex]Br_2[/tex] is produced.
Thus bromine is produced at anode.
