We have the representation of this problem in the figure below. As we have a 10.3 mile race, then the equation is fulfilled as:
[tex]d = 10.3mi = d_{1}+ d_{2}[/tex]
We know that there is a water station that is twice as far from the starting line as from the finish line, then:
[tex]d_{2}=2d_{1}[/tex]
So:
[tex]d_{1} +2d_{1}=10.3[/tex]
∴ [tex]d_{1}=3.43mi[/tex]
and [tex]d_{2}=2(3.43)=6.86mi[/tex]
Finally, the distance of the runner from the finish line is:
[tex]6.86mi[/tex]
