Respuesta :
The average speed is defined as the total distance covered divided by the time interval.
First of all we need to convert the time interval from minutes to hours, so:
[tex]121212min(\frac{1h}{60min}) = 2020.2h[/tex]
We know that the distance, speed and time are related as follows:
[tex]d = vt[/tex]
Thus, the distance covered from home to the grocery store is:
[tex]d = 151515(2020.2)=306090603mi[/tex]
So, the total distance covered for the entire trip from home to the grocery store and back is:
[tex]d_{t} = 2(306090603) = 612181206mi[/tex]
We need to the total time interval, that is:
[tex]t = t_{1} + t_{2} = 2020.2h + t_{2}[/tex]
So, it is necessary to find [tex]t_{2} [/tex] as:
[tex]t_{2} = \frac{306090603mi}{303030mph} = 1010.1h[/tex]
In this way:
[tex]t = 2020.2h + 1010.1h = 3030.3h [/tex]
Finally, his average speed for the entire trip from home to the grocery store and back is:
[tex]v_{a} = \frac{d_{t}}{t} = \frac{612181206mi}{3030.3h} = 202020,ph[/tex]
First of all we need to convert the time interval from minutes to hours, so:
[tex]121212min(\frac{1h}{60min}) = 2020.2h[/tex]
We know that the distance, speed and time are related as follows:
[tex]d = vt[/tex]
Thus, the distance covered from home to the grocery store is:
[tex]d = 151515(2020.2)=306090603mi[/tex]
So, the total distance covered for the entire trip from home to the grocery store and back is:
[tex]d_{t} = 2(306090603) = 612181206mi[/tex]
We need to the total time interval, that is:
[tex]t = t_{1} + t_{2} = 2020.2h + t_{2}[/tex]
So, it is necessary to find [tex]t_{2} [/tex] as:
[tex]t_{2} = \frac{306090603mi}{303030mph} = 1010.1h[/tex]
In this way:
[tex]t = 2020.2h + 1010.1h = 3030.3h [/tex]
Finally, his average speed for the entire trip from home to the grocery store and back is:
[tex]v_{a} = \frac{d_{t}}{t} = \frac{612181206mi}{3030.3h} = 202020,ph[/tex]
Answer: The average speed for the entire trip from home to the grocery store and back is 20 mph.
Step-by-step explanation:
Since we have given that
Ishan traveled uphill to the grocery store for 12 minutes at just 15 mph.
So, Time taken by him = 12 minutes
Speed = 15 mph
So, distance traveled = Speed × time
So, Distance becomes [tex]15\times \dfrac{12}{60}=\dfrac{180}{60}=3\ miles[/tex]
Again, he traveled back home along the same path downhill = 180 miles
Speed of covering downhill = 30 mph
so, Time taken [tex]\dfrac{Distance}{Speed}=\dfrac{3}{30}=\dfrac{1}{10}\ hours[/tex]
Since we know the formula for "Average speed ":
[tex]\dfrac{Total\ distance}{Total\ Time}\\\\\\=\dfrac{3+3}{\dfrac{12}{60}+\dfrac{1}{10}}\\\\\\=\dfrac{6}{\dfrac{1}{5}+\dfrac{1}{10}}\\\\\\=\dfrac{6\times 10}{2+1}\\\\\\=\dfrac{6\times 10}{3}\\\\\\=20\ mph[/tex]
Hence, the average speed for the entire trip from home to the grocery store and back is 20 mph.
