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[tex]5 log(x) + 3 log( {x}^{2} ) [/tex]

[tex] = log( {x}^{5} ) + log( {x}^{6} ) [/tex]

[tex] = log( {x}^{5} \times {x }^{6} ) [/tex]

[tex] = 11 log(x) [/tex]

Answer:

[tex]5 log x + 3 log x^{2} = 11 log x[/tex]

Step-by-step explanation:

Given the logarithmic  expression

[tex]5 logx + 3 log x^2[/tex]

Logarithm rule: when we take log with any number raise to power x

Then the power x move down before the log  and write log with the base of  number

For example : Let we take a number [tex]2^x[/tex]

When we take log then power x go down and write before the log and take log with the given base of that number

Therefore we can write as x log 2

Now , we have logarithmic expression

[tex]5logx + 3 log x^2[/tex]

= [tex]5 logx + 6 log x[/tex]

= [tex]11 logx[/tex]

Hence, the logarithmic expression  [tex]5 log x + 3 log x^2[/tex] is equivalent to [tex]11 log x[/tex].

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