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The absolute (or total) pressure at the bottom of a cylindrical container with a cross-sectional area of 47.0 cm2 and holding a fluid of density 560 kg/m3 is 115 kpa. (a) determine the depth of the fluid.

Respuesta :

smmwaite
The pressure in fluids is given by, 
Pressure = density × gravity × depth 

So therefore, 
115000 = 560 × 9.8 × depth

making the depth the subject of the formula, 
Depth = 115,000 ÷ (560×9.8)
           = 115,000 ÷ 5,488
           = 20.9548 m

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