Respuesta :

Hello there, I believe you are practicing for the AP Chemistry exam. If you are, so am I :) 

Anyways, the answer is that some gas will be produced but less than the amount of gas produced by Li.

To understand this, we first need to look at the number of moles we have of each substance. For 0.35 grams of Li, we have an estimated value (I am estimating because the multiple choice of the exam is non calculator) of 0.05 moles. For K however, we have an estimated value of 0.01 moles used.

Now look at the two equations: 2K +3H2O ---> 2H2 + 2K(OH)
                                                  2Li +3H2o ---> 2H2 +2Li(OH)
In the question, it specifies that H2 gas is produced as a product. Because both equations produce H2 in a 2:2  ratio (or a simplified ratio of 1:1), 0.05 moles of H2 will be produced for the Li equation, while 0.01 moles of H2 will be produced for the K equation. Therefore, the Li produces more moles of gas than K. 

I hope that makes sense. Happy studying :)

The effect on the amount of gas produced if the experiment is repeated using 0.35g of potassium is that less amount of hydrogen gas is produced.

What is the stoichiometry?

Stoichiometry of any reaction gives idea about the amount of species present and before the completion of the reaction.

Chemical reaction with repect to Lithium (Li) and Potassium (K) will be represented as:

2K + 3H₂O → 2H₂ + 2KOH

2Li + 3H₂O → 2H₂ + 2LiOH

From the stoichiometry of the reaction it is clear that 2 moles of K & Li produces 2 moles of hydrogen gas.

Moles will be calculated as:

n = W/M, where

W = given mass = 0.35g

M = molar mass

Moles of 0.35g Li = 0.35 / 6.9 = 0.0507 moles

Moles of 0.35g K = 0.35 / 39 = 0.0089 moles

From the moles of both elements it is clear that lithium will produce more gas.

Hence on replacing lithium with potassium, less gas will be produced.

To know more about moles, visit the below link:
https://brainly.com/question/15373263

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