Respuesta :

kenmyna
The amount  of a 0.225 M  KCl solution  that contain  55.8 g KCl  is calculated  as  below

calculate  the  moles  of KCl =mass/  molar  mass

=55.8 g/74.5 g/mol = 0.749  moles

volume  of KCl = moles/molarity

= 0.749/0.225 = 3.329 liters  of KCl

Answer : The volume of solution is, 3.33 liter

Explanation : Given,

Mass of KCl = 55.8 g

Molar mass of KCl = 74.5 g/mole

Molarity = 0.225 M

Molarity : It is defined as the number of moles of solute present in one liter of solution.

In this question, the solute is KCl.

Formula used :

[tex]Molarity=\frac{w_b}{M_b\times V}[/tex]

where,

[tex]w_b[/tex] = mass of solute KCl

[tex]M_b[/tex] = molar mass of solute KCl

V = volume of solution = ?

Now put all the given values in the above formula, we get the molarity of the solution.

[tex]0.225mole/L=\frac{55.8g}{74.5g/mole\times V}[/tex]

[tex]V=3.33L[/tex]

Therefore, the volume of solution is, 3.33 liter

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