Answer:
[tex]\text{The solutions are 14 and 9}[/tex]
Step-by-step explanation:
Given the equation
[tex]2a^2-46a+252=0[/tex]
we have to find the solution of above equation by using quadratic formula.
Equation:[tex]2a^2-46a+252=0[/tex]
[tex]\text{Comparing above with standard equation }ax^2+bx+c=0\text{, we get}[/tex]
a=2, b=-46, c=252
By quadratic formula
[tex]a=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
[tex]a=\frac{-(-46)\pm \sqrt{(-46)^2-4(2)(252)}}{2(2)}[/tex]
[tex]a=\frac{46\pm \sqrt{100}}{4}[/tex]
[tex]a=\frac{46\pm 10}{4}[/tex]
[tex]a=\frac{56}{4},\frac{36}{4}[/tex]
[tex]\text{The solutions are 14 and 9}[/tex]
