Answer is: chlorine and sodium.
Molten sodium chloride is separeted::
2NaCl(l) → 2Na(l) + Cl₂(g),
but first ionic bonds in this salt are separeted
because of heat:
NaCl(l) → Na⁺(l) + Cl⁻(l).
Reaction of reduction
at cathode(-): Na⁺(l) + e⁻ → Na⁰(l) /×2.
2Na⁺(l) + 2e⁻ → 2Na(l)
Reaction of oxidation
at anode(+): 2Cl⁻(l) → Cl₂(g) + 2e⁻.
The anode is positive
and the cathode is negative.
