Respuesta :

jushmk
Using the given relationship between electrons and coulombs;

1 e = 1.60*10^-19 C

Total charge = 3.0*10^15*1.6*10^-19 = 4.8*10^-4 C

Current = Coulombs/Time = (4.8*10^-4)/4 = 1.2*10^-4 C/s = 1.2*10^-4 Amps

Current in amperes, A = 0.00012 A = 0.12 mA
facundo3141592

The current through the wire is of 0.00012 amperes.

How to find the current?

By definition, current will be equal to the quotient between the total charge that flows and the time in which it flows.

Here we have 3.0*10^15 electrons, each one with charge:

e = 1.6*10^(-19) C

Then the total charge that we have is:

Q = (1.6*10^(-19) C)*(3.0*10^15) = 0.00048 C

Finally, the current is:

I = Q/T

where:

  • Q = 0.00048 C
  • T = 4.0 s

I = (0.00048 C)/(4s) = 0.00012 A

If you want to learn more about current, you can read:

https://brainly.com/question/14010194

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