The number of liters of 0.45 m Hcl that will be required to titrate completely is calculated as below
write the equation for reaction
that is NaOH + HCl = NaCl + H2O
find the moles of NaOH used = molarity x volume
= 1.2 x0.22 = 0.264 moles
by use mole ratio between NaOH to HCl which is 1:1 the moles of HCl =0.264 moles
volume =moles/molarity
=0.264/0.45= 0.587 liters of HCL
