Respuesta :
The plastic rod is made of insulator (plastic), so it does not allow charges moving from one sphere to another. This means that all the electrons given to sphere A will remain on sphere A.
The number of electrons initially given to sphere A is [tex]N=1.0 \cdot 10^{12}[/tex], and since the charge of 1 electron is [tex]e=-1.6 \cdot 10^{-19} C[/tex], the net charge left on sphere A after the removal of the rod will be
[tex]Q=N e = 1.0 \cdot 10^{12}(-1.6 \cdot 10^{-19} C)=-1.6.0 \cdot 10^{-7} C [/tex]
The number of electrons initially given to sphere A is [tex]N=1.0 \cdot 10^{12}[/tex], and since the charge of 1 electron is [tex]e=-1.6 \cdot 10^{-19} C[/tex], the net charge left on sphere A after the removal of the rod will be
[tex]Q=N e = 1.0 \cdot 10^{12}(-1.6 \cdot 10^{-19} C)=-1.6.0 \cdot 10^{-7} C [/tex]
The net charge on the sphere A after the removal of the connecting road will be [tex]\boxed{-1.6\times10^{-7}\text{ C}}[/tex].
Explanation:
An electron is considered to be the basic unit of charge. The amount of charge present on an electron is [tex]1.6\times10^{-19}\text{ C}[/tex].
When a number of electrons are transferred to one sphere, the sphere gets negatively charge. The amount of charge on the sphere is given by:
[tex]\boxed{Q=-n.e}[/tex]
Here, [tex]Q[/tex] is the charge on the sphere, [tex]n[/tex] is the number of electrons and [tex]e[/tex] is the amount of charge on one electron.
Substitute the value in above expression.
[tex]Q_{A}=-(1.0\times10^{12})(1.6\times10^{-19})}\\Q_A=-1.6\times10^{-7}\text{ C}[/tex]
Now, the second sphere is still neutral as it has no charge. When the two spheres are connected to one another by means of a plastic rod, there will be no transfer of the charge from one sphere to the other.
In order to initiate the transfer of the charge from one body to the other, the medium connecting the two spheres should be of conducting nature. But in this case, the connecting rod is plastic therefore, there will be no transfer of charge between the spheres.
So, the charge on both the spheres remains the same as it was at the beginning when the plastic rod was connected between them.
Thus, The net charge on the sphere A after the removal of the connecting road will be [tex]\boxed{-1.6\times10^{-7}\text{ C}}[/tex].
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Answer Details:
Grade: College
Subject: Physics
Chapter: Electrostatics
Keywords:
charge, spheres, connected, plastic rod, connecting, initially, neutral, electron, negative, transferred, net.
