Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the acceleration due to gravity is 1.63 m/s2 .
The period of a pendulum is given by [tex]T=2 \pi \sqrt{ \frac{L}{g} } [/tex] where L is the pendulum length and g is the gravitational acceleration.
We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find: [tex] \frac{T_m}{T_e} = \frac{2 \pi \sqrt{ \frac{L}{g_m} } }{2 \pi \sqrt{ \frac{L}{g_e} } }= \sqrt{ \frac{g_e}{g_m} } [/tex] where the labels m and e refer to "Moon" and "Earth".
Since the gravitational acceleration on Earth is [tex]g_e = 9.81 m/s^2[/tex] while on the Moon is [tex]g_m=1.63 m/s^2[/tex], the ratio between the period on the Moon and on Earth is [tex] \frac{T_m}{T_e}= \sqrt{ \frac{g_e}{g_m} }= \sqrt{ \frac{9.81 m/s^2}{1.63 m/s^2} }=2.45 [/tex]
