The work done by the gas is :
[tex]\texttt{ }[/tex]
The Ideal Gas Law that needs to be recalled is:
[tex]\large {\boxed {PV = nRT} }[/tex]
P = Pressure (Pa)
V = Volume (m³)
n = number of moles (moles)
R = Gas Constant (8.314 J/mol K)
T = Absolute Temperature (K)
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Complete Question:
Calculate [tex]W_A[/tex], the work done by the gas as it expands along path A from [tex]V_0[/tex] to [tex]V_A = R_V V_0[/tex].
Express [tex]W_A[/tex in terms of [tex]p_0 , V_0,[/tex] and [tex]R_V[/tex]
Given:
initial volume = Vo
final volume = V_A
constant pressure = p_o
Asked:
word done by the gas = W_A = ?
Solution:
Work done by the gas is the area under Pressure Vs Volume Graph.
[tex]\texttt{Work} = \texttt{Area Under P Vs V Graph}[/tex]
[tex]W_A = p_0 \times ( V_A - V_0 )[/tex]
[tex]W_A = p_0 \times ( R_V V_0 - V_0 )[/tex]
[tex]W_A = p_0 V_0 \times ( R_V - 1 )[/tex]
[tex]\large {\boxed {W_A = p_0 V_0 ( R_V - 1 )} }[/tex]
[tex]\texttt{ }[/tex]
[tex]\texttt{ }[/tex]
Grade: High School
Subject: Physics
Chapter: Pressure
