Whats the distance from point y to qx in the figure

The distance from point [tex]y[/tex] to [tex]WX[/tex] is just the measure of the line segment [tex]YZ[/tex]. Notice that [tex]YZ[/tex] is one of the sides of the right triangle [tex]XYZ[/tex], so to find its length we are going to use the Pythagorean theorem:
[tex](YZ)^2=(XY)^2-(XZ)^2[/tex]
[tex](YZ)^2=(10 \sqrt{2} )^2-10^2[/tex]
[tex](YZ)^2=200-100[/tex]
[tex](YZ)^2=100[/tex]
[tex]YZ= \sqrt{100} [/tex]
[tex]YZ=10[/tex]

We can conclude that the correct answer is B. 10

tiff321 tiff321 · Answer 2 · 2018-05-05T06:56:18+02:00

Because the triangle XYZ is a right triangle, you can use the pythagorean theorm which is a^2 + b^2 = c^2
the c^2 is always the hypotenuse and the a and b don't matter
10^2 + b^2 = (10 rad 2)^2
100 + b^2 = (10 rad 2)(10 rad 2)
100 + b^2 = 100 * 2 --> rad 2 times rad 2 = 2 (the radical cancels out)
100 + b^2 = 200
100-100 + b^2 = 200-100
b^2 = 100
b = rad 100
b = 10
the distance from point Y to WX is 10 (answer is B)