[tex]50.5 g C_{5}{H}_{12}
Molar mass C_{5}H_{12} =5*12+12*1=72 g/mol
50.5 g* (1 mol/72 g)=0.706 mol C_{5}H_{12}
C_{5}H_{12} + 8O_{2} ---\ \textgreater \ 5CO_{2} +6 H_{2}O
1 mol C_{5}H_{12} ----- 6 mol H_{2}O
0.706 mol C_{5}H_{12} --- x mol H_{2}O
x= (0.706*6)/1= 4.24 mol H_{2}O
Under STP water is liquid.
M(H_{2}O})=2*1.0+16.0=18.0 \frac{g}{mol}
4.24 mol H_{2}O * \frac{18.0 g}{1 mol} = 76.3 g H_{2}O
Density H_{2}O = 1 \frac{g}{ml}
76.3 g /(1 g/ml) = 76.3 ml of water
Answer 76.3 ml of the water.
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